y=-1/2x^2-2x-2

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Solution for y=-1/2x^2-2x-2 equation:


x in (-oo:+oo)

y = (-1/2)*x^2-(2*x)-2 // - (-1/2)*x^2-(2*x)-2

2*x-((-1/2)*x^2)+y+2 = 0

(1/2)*x^2+2*x+y+2 = 0

1/2*x^2+2*x+y+2 = 0

DELTA = 2^2-(1/2*4*(y+2))

DELTA = 4-2*(y+2)

4-2*(y+2) = 0

4-2*(y+2) = 0

-2*y = 0

-2*y = 0

-2*y = 0 // : -2

y = 0

DELTA = 0 <=> t_1 = 0

x = -2/(1/2*2) i y = 0

x = -2 i y = 0

( x = ((4-2*(y+2))^(1/2)-2)/(1/2*2) or x = (-(4-2*(y+2))^(1/2)-2)/(1/2*2) ) i y > 0

( x = (4-2*(y+2))^(1/2)-2 or x = -((4-2*(y+2))^(1/2)+2) ) i y > 0

y+0 > 0

y > 0

y+0 > 0 // - 0

y > 0

x in { -2, (4-2*(y+2))^(1/2)-2, -((4-2*(y+2))^(1/2)+2) }

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